Evaluate a Function
Evaluate the function at the given value of the independent variable and simplify.
-$$f ( x ) = \frac { x ^ { 2 } - 3 } { x ^ { 3 } - 6 x } ; f ( 2 )$$
A) $- \frac { 1 } { 4 }$
B) $\frac { 1 } { 8 }$
C) $\frac { 1 } { 2 }$
D) - 1

Question

Quizplus · Accepted Answer

To evaluate $f(2)$, substitute $x = 2$ into the function: $f(2) = \frac{2^2 - 3}{2^3 - 6 \cdot 2} = \frac{4 - 3}{8 - 12} = \frac{1}{-4} = -\frac{1}{4}$.

Evaluate a Function Evaluate the Function at the Given Value f(x)=x2−3x3−6x;f(2)f ( x ) = \frac { x ^ { 2 } - 3 } { x ^ { 3 } - 6 x } ; f ( 2 )f(x)=x3−6xx2−3​;f(2)

Evaluate a Function
Evaluate the Function at the Given Value $f ( x ) = \frac { x ^ { 2 } - 3 } { x ^ { 3 } - 6 x } ; f ( 2 )$