Is the ordered triple a solution to the given system of equations?
-$$\begin{array} { r }
( - 2 , - 1,5 ) \
x - y + z = 4 \
2 x - 8 y - 3 z = 24 \
3 x + 4 y + 2 z = 7
\end{array}$$
A) No
B) Yes

Question

Is the ordered triple a solution to the given system of equations?
-$$\begin{array} { r } 
( - 2 , - 1,5 ) \
x - y + z = 4 \
2 x - 8 y - 3 z = 24 \
3 x + 4 y + 2 z = 7
\end{array}$$
A) No
B) Yes

Quizplus · Accepted Answer

To check if the ordered triple is a solution to the system of equations, we need to substitute each value into the equations and see if they are all true.

Substituting $x=-2$, $y=-1$, and $z=5$, we get:

\begin{align*}
x-y+z &=-2-(-1)+5=2 \
2x-8y-3z &=2(-2)-8(-1)-3(5)=-6 \
3x+4y+2z &=3(-2)+4(-1)+2(5)=0
\end{align*}

The last equation, $3x+4y+2z=0$, is not true when we substitute the values of $x$, $y$ and $z$ from the ordered triple. Therefore, the ordered triple is not a solution to the system of equations. The correct answer is (A).

Is the Ordered Triple a Solution to the Given System (−2,−1,5)x−y+z=42x−8y−3z=243x+4y+2z=7\begin{array} { r } ( - 2 , - 1,5 ) \\x - y + z = 4 \\2 x - 8 y - 3 z = 24 \\3 x + 4 y + 2 z = 7\end{array}(−2,−1,5)x−y+z=42x−8y−3z=243x+4y+2z=7​

Is the Ordered Triple a Solution to the Given System $\begin{array} { r } ( - 2 , - 1,5 ) \\x - y + z = 4 \\2 x - 8 y - 3 z = 24 \\3 x + 4 y + 2 z = 7\end{array}$