Find the first four terms of the given sequence.
-$$a _ { 1 } = 6 , a _ { n } = \frac { ( - 1 ) ^ { n - 1 } } { a _ { n } - 1 }$$
A) $6 , - \frac { 1 } { 6 } , 6 , - \frac { 1 } { 6 }$
B) $- 6 , \frac { 1 } { 2 } , - \frac { 1 } { 3 } , \frac { 1 } { 4 }$
C) $6 , - \frac { 1 } { 6 } , \frac { 1 } { 36 } , - \frac { 1 } { 216 }$
D) $6 , - \frac { 1 } { 6 } , - 6 , \frac { 1 } { 6 }$

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The Answer of Find the first four terms of the given sequence.
-$$a _ { 1 } = 6 , a _ { n } = \frac { ( - 1 ) ^ { n - 1 } } { a _ { n } - 1 }$$
A) $6 , - \frac { 1 } { 6 } , 6 , - \frac { 1 } { 6 }$
B) $- 6 , \frac { 1 } { 2 } , - \frac { 1 } { 3 } , \frac { 1 } { 4 }$
C) $6 , - \frac { 1 } { 6 } , \frac { 1 } { 36 } , - \frac { 1 } { 216 }$
D) $6 , - \frac { 1 } { 6 } , - 6 , \frac { 1 } { 6 }$

Find the First Four Terms of the Given Sequence a1=6,an=(−1)n−1an−1a _ { 1 } = 6 , a _ { n } = \frac { ( - 1 ) ^ { n - 1 } } { a _ { n } - 1 }a1​=6,an​=an​−1(−1)n−1​

Find the First Four Terms of the Given Sequence $a _ { 1 } = 6 , a _ { n } = \frac { ( - 1 ) ^ { n - 1 } } { a _ { n } - 1 }$