Find an equation of the circle with the given center and radius.
-Center (0, 0), radius 19
A) $x ^ { 2 } + y ^ { 2 } = 361$
B) $( x - 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 19$
C) $x ^ { 2 } + y ^ { 2 } = 19$
D) $x ^ { 2 } + y ^ { 2 } = \sqrt { 19 }$

Question

Find an equation of the circle with the given center and radius.
-Center (0, 0), radius 19 
A) $x ^ { 2 } + y ^ { 2 } = 361$
B) $( x - 1 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 19$
C) $x ^ { 2 } + y ^ { 2 } = 19$
D) $x ^ { 2 } + y ^ { 2 } = \sqrt { 19 }$

Quizplus · Accepted Answer

The equation of a circle with center $(a,b)$ and radius $r$ is given by $(x-a)^2+(y-b)^2=r^2$. Therefore, substituting the given values, we get $(x-0)^2+(y-0)^2=19^2$, which simplifies to $x^2+y^2=361$. So, the correct choice is A.

Find an Equation of the Circle with the Given Center x2+y2=361x ^ { 2 } + y ^ { 2 } = 361x2+y2=361

Find an Equation of the Circle with the Given Center $x ^ { 2 } + y ^ { 2 } = 361$