The following output from MINITAB presents the results of a hypothesis test for a population mean $\mu .$ $$\begin{array}{l}
\text { Test of mu } = 33 \text { vs. not } = 33\\
\begin{array} { l r r c c r r }
\text { N } & \text { Mean } & \text { StDev } & \text { SE Mean } & 95 \% \text { CI } & \text { T } & \text { P } \
54 & 30.19 & 35.328010 & 4.807533 & ( 20.547241,39.832759 ) & - 0.584499 & 0.561365 \
\hline
\end{array}
\end{array}$$ Do you reject $H _ { 0 }$ at the $a = 0.05$ level of significance?

Question

The following output from MINITAB presents the results of a hypothesis test for a population mean $\mu .$ $$\begin{array}{l}
\text { Test of mu } = 33 \text { vs. not } = 33\\
\begin{array} { l r r c c r r } 
\text { N } & \text { Mean } & \text { StDev } & \text { SE Mean } & 95 \% \text { CI } & \text { T } & \text { P } \
54 & 30.19 & 35.328010 & 4.807533 & ( 20.547241,39.832759 ) & - 0.584499 & 0.561365 \
\hline
\end{array}
\end{array}$$ Do you reject $H _ { 0 }$ at the $a = 0.05$ level of significance?

Quizplus · Accepted Answer

The P-value for the test is 0.561365, which is greater than the significance level of 0.05. Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim that the population mean is different from 33.

The Following Output from MINITAB Presents the Results of a Hypothesis