The following MINITAB output presents the least squares regression line for predicting the price of a certain commodity from the price of a barrel of oil.
The regression equation is
$$
\text { Commodity }=30.483819+1.633495 \text { Oil }
$$

$\begin{array}{lrrrr}
\text { Predictor } & \text { Coef } & \text { SE Coef } & \mathrm{T} & \mathrm{P} \
\text { Constant } & 30.483819 & 33.659605 & 0.90565 & 0.416341 \
\text { Oil } & 1.633495 & 0.33602 & 4.861308 & 0.008272 \
\hline
\end{array}$

Write the equation of the least-squares regression line.
A) y=30.483819+1.633495 x
B) y=0.90565+4.861308 x
C) y=0.416341+0.008272 x
D) y=1.633495+30.483819 x

Question

The following MINITAB output presents the least squares regression line for predicting the price of a certain commodity from the price of a barrel of oil. 
The regression equation is
$$
\text { Commodity }=30.483819+1.633495 \text { Oil }
$$

$\begin{array}{lrrrr}
\text { Predictor } & \text { Coef } & \text { SE Coef } & \mathrm{T} & \mathrm{P} \
\text { Constant } & 30.483819 & 33.659605 & 0.90565 & 0.416341 \
\text { Oil } & 1.633495 & 0.33602 & 4.861308 & 0.008272 \
\hline
\end{array}$

Write the equation of the least-squares regression line. 
A) y=30.483819+1.633495 x
B) y=0.90565+4.861308 x
C) y=0.416341+0.008272 x
D) y=1.633495+30.483819 x

Quizplus · Accepted Answer

The equation of the least-squares regression line is given by 
y = b0 + b1x, where b0 is the intercept and b1 is the slope coefficient. From the MINITAB output, we can see that the intercept is 30.483819, and the slope coefficient is 1.633495, so the regression equation is y = 30.483819 + 1.633495x. Therefore, the correct choice is A.

The Following MINITAB Output Presents the Least Squares Regression Line Commodity =30.483819+1.633495 Oil \text { Commodity }=30.483819+1.633495 \text { Oil } Commodity =30.483819+1.633495 Oil

The Following MINITAB Output Presents the Least Squares Regression Line $\text { Commodity }=30.483819+1.633495 \text { Oil }$