The Following MINITAB Output Display Presents the Results of a Hypothesis

The following MINITAB output display presents the results of a hypothesis test for the difference $\mu _ { 1 } - \mu _ { 2 }$ between two population means.
$\begin{array}{l}\text { Two-sample T for X1 vs X2 }\\\begin{array}{rrrcc} & \mathrm{N} & \text { Mean } & \text { StDev } & \text { SE Mean } \\\text { A } & 7 & 145.411 & 24.669 & 9.324 \\\text { B } & 14 & 132.964 & 25.604 & 6.843\end{array}\end{array}$

Difference $=m u(X 1) -m u(X 2)$
Estimate for difference: $12.447$
$95 \%$ CI for difference: $(-10.222,35.116)$
T-Test of difference $=0($ vs not $=)$ : $\quad$ T-Value $=1.076209$
$\text { P-Value }=0.301402 \quad \text { DF }=13$

What is the alternate hypothesis?

A) $\mu _ { 1 } \neq \mu _ { 2 }$
B) $\mu _ { 1 } > \mu _ { 2 }$
C) $\mu _ { 1 } = \mu _ { 2 }$
D) $\mu _ { 1 } < \mu _ { 2 }$