The life expectancy E , in years, for a child born years after 2000 is given by $E = 76.62 + 0.18 t$ In what birth year would a child have a life expectancy of 77.7 years?
A) 2009
B) 2006
C) 2005
D) That life expectancy never occurs.

Question

The life expectancy E , in years, for a child born  years after 2000 is given by $E = 76.62 + 0.18 t$ In what birth year would a child have a life expectancy of 77.7 years?
A) 2009 
B) 2006 
C) 2005 
D) That life expectancy never occurs.

Quizplus · Accepted Answer

We are given the equation:
E = 76.62 + 0.18t
where t is the number of years after 2000.
We want to find the birth year for which the life expectancy is 77.7 years. So we need to set E equal to 77.7 and solve for t:
77.7 = 76.62 + 0.18t
0.18t = 1.08
t = 6
Since t represents the number of years after 2000, we can find the birth year by subtracting t from 2000:
2000 - 6 = 1994
So a child born in 1994 would have a life expectancy of 77.7 years. Therefore, the answer is B) 2006.

The Life Expectancy E , in Years, for a Child E=76.62+0.18tE = 76.62 + 0.18 tE=76.62+0.18t

The Life Expectancy E , in Years, for a Child $E = 76.62 + 0.18 t$