Jorge has his own business as a painter. The amounts he made in the last five months are shown below: $\begin{array} { l l l l l } \$ 2426 & \$ 2463 & \$ 1451 & \$ 2154 & \$ 1119 \end{array}$
Find the mean, median, and range of the data.
A) Mean $= \$ 1923$, Median $= \$ 2154$, Range $= - \$ 1344$
B) Mean $= \$ 1923$, Median $= \$ 2154$, Range $= \$ 1344$
C) Mean $= \$ 2154$, Median $= \$ 1923$, Range $= \$ 1344$

Question

Quizplus · Accepted Answer

To find the mean, we add up all the amounts and divide by the number of amounts:
\begin{align*}
\text{Mean} &= \frac{\$2426 + \$2463 + \$1451 + \$2154 + \$1119}{5} \
&= \frac{\$9613}{5} \
&= \$1923.20
\end{align*}
To find the median, we need to find the middle value. We can do this by putting the amounts in order from least to greatest:
$$\$1119, \$1451, \$2154, \$2426, \$2463$$
Since there is an odd number of amounts, the median is the middle value, which is $\$2154$.
To find the range, we subtract the smallest amount from the largest amount:
$$\$2463 - \$1119 = \$1344$$
Therefore, the best choice is B, where the mean is \$1923, the median is \$2154, and the range is \$1344.

Jorge Has His Own Business as a Painter $2426$2463$1451$2154$1119\begin{array} { l l l l l } \$ 2426 & \$ 2463 & \$ 1451 & \$ 2154 & \$ 1119 \end{array}$2426​$2463​$1451​$2154​$1119​

Jorge Has His Own Business as a Painter $\begin{array} { l l l l l } \$ 2426 & \$ 2463 & \$ 1451 & \$ 2154 & \$ 1119 \end{array}$