Express as a single logarithm.

Question

Quizplus · Accepted Answer

We can use the logarithmic identity: loga + logb = log(ab) to combine the three logarithms into one. Applying this to the given expression, we get:

log2(4) + log8(16) - log4(2)
= log2(2^2) + log2(2^4) - log2(2^(1/2))    (using the change of base formula)
= log2(2^2 * 2^4 / 2^(1/2))
= log2(2^(8/2) / 2^(1/2))
= log2(2^7)
= 7

Therefore, the expression can be simplified to log2(128), which is equivalent to B) 11eb69da_9f13_e433_af94_afd06750f321_TB8311_11.

Express as a Single Logarithm