Find the first derivative of w(x) = bx²+ x^u^. A)x² + ux^u^-1 B)2bx + ux C)2bx + u D)2bx + ux^u^-1

Question

Quizplus · Accepted Answer

The given function w(x) = bx^2 + x^u seems to have been encoded with placeholders for superscript (^{) and subscript (}), making it difficult to read directly. However, interpreting the placeholders as intended, the function simplifies to w(x) = bx^2 + x^u. The first derivative of bx^2 is 2bx, and the first derivative of x^u (using the power rule) is ux^(u-1). Therefore, the correct answer is D) 2bx + ux^(u-1).

Find the First Derivative of W(x) = Bx2 + Xu

Find the First Derivative of W(x) = Bx²+ X^u