If the $\left[ \mathrm { OH } ^ { - } \right]$ concentration is equal to 0.023M and the analytical concentration of the same base is equal to 0.494 M, its percentage ionization is _____.

Question

Quizplus · Accepted Answer

The percentage ionization is calculated by dividing the concentration of ionized base ($\left[ \mathrm { OH } ^ { - } \right]$ = 0.023M) by the initial concentration of the base before ionization (0.494M) and then multiplying by 100. So, $\frac{0.023}{0.494} \times 100 = 4.7\%$.

If The [OH−]\left[ \mathrm { OH } ^ { - } \right][OH−]

If The $\left[ \mathrm { OH } ^ { - } \right]$