Calculate the Equilibrium Constant K₃ for the Reaction At 785 ${ } ^ { \circ } \mathrm { C }$

Calculate the equilibrium constant K₃ for the reaction $\mathrm { CO } ( \mathrm { g } ) + 2 \mathrm { H } _ { 2 } \mathrm {~S} ( \mathrm {~g} ) f \quad \mathrm { CS } _ { 2 } ( \mathrm {~g} ) + \mathrm { H } _ { 2 } \mathrm { O } ( \mathrm { g } ) + \mathrm { H } _ { 2 } ( \mathrm {~g} )$ at 785 ${ } ^ { \circ } \mathrm { C }$ . Given that the equilibrium constant K₁ for the reaction $\mathrm { CO } ( \mathrm { g } ) + 3 \mathrm { H } _ { 2 } ( \mathrm {~g} ) f \quad \mathrm { CH } _ { 4 } ( \mathrm {~g} ) + \mathrm { H } _ { 2 } \mathrm { O } ( \mathrm { g } )$ is 7.34 $\times 10 ^ { - 2 }$ and the equilibrium constant K₂ for the reaction $\mathrm { CH } _ { 4 } ( \mathrm {~g} ) + 2 \mathrm { H } _ { 2 } \mathrm {~S} ( \mathrm {~g} ) f \quad \mathrm { CS } _ { 2 } ( \mathrm {~g} ) + 4 \mathrm { H } _ { 2 } ( \mathrm {~g} )$ is 2.89 $\times 10 ^ { 4 }$ .

A) 2.53 $\times 10 ^ { 2 }$
B) 7.34 $\times 10 ^ { - 2 }$
C) 2.89 $\times 10 ^ { 4 }$
D) 4.45 $\times 10 ^ { 3 }$
E) 2.12 $\times 10 ^ { 3 }$