Volume stress and strain: A solid steel sphere with a radius of 2.0 m falls off a ship and sinks to a depth where the pressure is 15 MN/m². The bulk modulus for this steel is 1.6 × 10¹¹N/m². What is the change in the radius of the sphere? A) -0.021 mm B) -4.2 mm C) -0.42 mm D) -0.19 mm E) -0.062 mm

Question

Quizplus · Accepted Answer

The change in volume can be calculated using the formula for volume strain: ΔV/V = -ΔP/K. The change in radius can then be derived from the change in volume.

Volume Stress and Strain: a Solid Steel Sphere with a Radius