Zeeman effect: An s state (l = 0) energy level is split into two levels by an applied magnetic field. A photon of microwave radiation having frequency 60 GHz induces a transition between the two levels. What is the magnitude of the applied magnetic field? (h = 6.626 × 10^-34 J ∙ s, Bohr magneton = μ_B = 9.27 × 10^-24 J/T)

Question

Quizplus · Accepted Answer

The energy difference between the two levels is given by:ΔE = hν = μBBwhere h is the Planck constant, ν is the frequency of the microwave radiation, μB is the Bohr magneton, and B is the magnetic field strength.Solving for B, we get:B = hν/μB = (6.626 × 10^-34 J ∙ s)(60 × 10^9 Hz)/(9.27 × 10^-24 J/T) = 2.1 T

Zeeman Effect: an S State (L = 0) Energy Level