Using the standard normal table, the total probabilities to the right of z = 2.0 and to the left of z = -2.0 is:
A) 0.0228
B) 0.4772
C) 0.9544
D) 0.0456
E) 0.1494

Question

Quizplus · Accepted Answer

The total probability to the right of z = 2.0 and to the left of z = -2.0 is found by looking up the z-score in the standard normal table, which gives the area to the left of z. For z = 2.0, the area to the left is 0.9772, so the area to the right is 1 - 0.9772 = 0.0228. Since the distribution is symmetrical, the area to the left of z = -2.0 is also 0.0228. Adding these two areas gives 0.0228 + 0.0228 = 0.0456.

Using the Standard Normal Table, the Total Probabilities to the Right