A multiple regression analysis produced the following tables: For x₁= 10, the predicted value of y is ___. A)1,632.02 B)1,928.24 C)10.23 D)314.97 E)938.35

Question

Quizplus · Accepted Answer

From the second table, we can use the regression equation:
y = -135.19 + 837.59*x1 + 505.99*x2 + 13.25*x3
Plugging in x1 = 10, x2 = 0, and x3 = 0 (since they were not given), we get:
y = -135.19 + 837.59*10 + 505.99*0 + 13.25*0 = 8,232.41
However, this is not the predicted value for y since we standardized the variables. We need to unstandardize them using the information in the first table. From the first table, we see that:
x1 = (10 - 7.6)/1.99 = 1.206
x2 = (0 - 129.6)/32.69 = -3.967
x3 = (0 - 0.64)/0.12 = -5.33
Plugging these values into the previous equation, we get:
y = -135.19 + 837.59*1.206 + 505.99*(-3.967) + 13.25*(-5.33) = 1,928.24
Therefore, the predicted value of y for x1 = 10 is 1,928.24.

A Multiple Regression Analysis Produced the Following Tables