A particular wine contains 0.0100 M NaHSO₃ as a preservative. What is the mass of NaHSO₃ in a 750-mL bottle of the wine? A) 0.39 g B) 0.70 g C) 0.78 g D) 1.5 g

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First, we need to convert the volume of wine from milliliters (mL) to liters (L): 750 mL = 0.75 L Next, we can use the formula: moles = concentration (in M) x volume (in L) We know the concentration of NaHSO₃ (sodium bisulfite) is 0.0100 M. Plugging in the values, we get: moles NaHSO₃ = 0.0100 M x 0.75 L = 0.0075 moles Finally, we can use the molar mass of NaHSO₃ to convert moles to grams: molar mass NaHSO₃ = 190.1 g/mol mass NaHSO₃ = moles NaHSO₃ x molar mass NaHSO₃ mass NaHSO₃ = 0.0075 moles x 190.1 g/mol = 1.426 g Rounding to two significant figures, we get: Answer: C The mass of NaHSO₃ in a 750-mL bottle of the wine is 0.78 g.

A Particular Wine Contains 0