The metabolism of one mole of glucose, C₆H₁₂O₆, releases 6.70 × 10² kcal of heat. How much heat is released by the combustion of 50.0 g of glucose?

Question

Quizplus · Accepted Answer

To find the heat released by the combustion of 50.0 g of glucose, first, calculate the molar mass of glucose (C6H12O6), which is approximately 180.16 g/mol. Then, determine how many moles of glucose are in 50.0 g by dividing the mass of glucose by its molar mass (50.0 g / 180.16 g/mol ≈ 0.277 moles). Since the combustion of one mole of glucose releases 6.70 × 10^12 kcal, the heat released by 0.277 moles is 0.277 moles × 6.70 × 10^12 kcal/mole ≈ 1.86 × 10^12 kcal, or 186 kcal when rounded to three significant figures.

The Metabolism of One Mole of Glucose, C6H12O6, Releases 6

The Metabolism of One Mole of Glucose, C₆H₁₂O₆, Releases 6