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Greengrow, Inc

Question 62

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Greengrow, Inc.is evaluating three new fertilizer mixes.During a trial period, four young plants of equal size were randomly assigned to each fertilizer mix.Plant heights (in centimeters) at the end of the trial period are shown below: Greengrow, Inc.is evaluating three new fertilizer mixes.During a trial period, four young plants of equal size were randomly assigned to each fertilizer mix.Plant heights (in centimeters)  at the end of the trial period are shown below:   You are to use the sample data to test the null hypothesis that the average heights for the three populations represented here are the same, using a significance level of 5%.Compute the F value (F<sub>sta</sub><sub>t</sub>)  for the test and report your conclusion. A) F<sub>stat</sub> = 3.248.Since F<sub>stat</sub> is less than the critical F value, we cannot reject the  no difference in population means  null hypothesis. B) F<sub>stat</sub> = 5.655.Since F<sub>stat</sub> is greater than the critical F value, we can reject the  no difference in population means  null hypothesis. C) F<sub>stat</sub> = 7.323.Since F<sub>stat</sub> is greater than the critical F value, we can reject the  no difference in population means  null hypothesis. D) F<sub>stat</sub> = 0.542.Since F<sub>stat</sub> is less than the critical F value, we cannot reject the  no difference in population means  null hypothesis. You are to use the sample data to test the null hypothesis that the average heights for the three populations represented here are the same, using a significance level of 5%.Compute the F value (Fstat) for the test and report your conclusion.


A) Fstat = 3.248.Since Fstat is less than the critical F value, we cannot reject the "no difference in population means" null hypothesis.
B) Fstat = 5.655.Since Fstat is greater than the critical F value, we can reject the "no difference in population means" null hypothesis.
C) Fstat = 7.323.Since Fstat is greater than the critical F value, we can reject the "no difference in population means" null hypothesis.
D) Fstat = 0.542.Since Fstat is less than the critical F value, we cannot reject the "no difference in population means" null hypothesis.

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