Greengrow, Inc.is evaluating three new fertilizer mixes.During a trial period, four young plants of equal size were randomly assigned to each fertilizer mix.Plant heights (in centimeters) at the end of the trial period are shown below: You are to use the sample data to test the null hypothesis that the average heights for the three populations represented here are the same, using a significance level of 5%.Compute the F value (Fstat) for the test and report your conclusion.
A) Fstat = 3.248.Since Fstat is less than the critical F value, we cannot reject the "no difference in population means" null hypothesis.
B) Fstat = 5.655.Since Fstat is greater than the critical F value, we can reject the "no difference in population means" null hypothesis.
C) Fstat = 7.323.Since Fstat is greater than the critical F value, we can reject the "no difference in population means" null hypothesis.
D) Fstat = 0.542.Since Fstat is less than the critical F value, we cannot reject the "no difference in population means" null hypothesis.
Correct Answer:
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