Charanka Solar Park in India reports that it produces an average of 16,400 kilowatt hours (kwh) of electricity per day, with a standard deviation of 2200 kwh.If this electrical output has a normal distribution, for what proportion of days would we expect the day's output to be less than 12000 kwh?
A).0112
B).0562
C).0228
D).0781
E).1067

Question

Quizplus · Accepted Answer

To find the proportion of days with output less than 12000 kwh, calculate the z-score: z = (12000 - 16400) / 2200 = -2. The z-score of -2 corresponds to a cumulative probability of 0.0228 in a standard normal distribution.

Charanka Solar Park in India Reports That It Produces an Average