Given the Thermochemical Equations, B₂O₃(s) + 3H₂O(g) → 3O₂(g)

Given the thermochemical equations, B₂O₃(s) + 3H₂O(g) → 3O₂(g) + B₂H₆(g) ΔH = −2,035 kJ
H₂O(ℓ) → H₂O(g) ΔH = 44 kJ
H₂ (g) + ½O₂(g) → H₂O(ℓ) ΔH = −286 kJ
2B(s) + 3H₂(g) → B₂H₆(g) ΔH = 36 kJ
What is the ΔH_f for 4B(s) + 3O₂(g) → 2B₂O₃(s) ?

A) +1,273 kJ
B) +2,690 kJ
C) -1,273 kJ
D) -5,594 kJ
E) +636.5 kJ