Given the following parameters,what would the reabsorption pressure be?
- blood capillary pressure at arteriolar end of tissue capillaries: 35 mm Hg
- blood capillary pressure at venule end of tissue capillaries: 15 mm Hg
- blood-colloid osmotic pressure: 22 mm Hg
- interstitial-fluid hydrostatic pressure: 1 mm Hg
- interstitial-fluid-colloid osmotic pressure: 0 mm Hg

Question

Quizplus · Accepted Answer

The reabsorption pressure is calculated by subtracting the forces that push fluid out of the capillary from the forces that push it back in. The forces pushing fluid out are the blood capillary pressure at the arteriolar end (35 mm Hg) and the interstitial fluid hydrostatic pressure (1 mm Hg), for a total of 36 mm Hg. The forces pushing fluid back in are the blood colloid osmotic pressure (22 mm Hg) and the blood capillary pressure at the venule end (15 mm Hg), for a total of 37 mm Hg. Subtracting the forces pushing fluid out from the forces pushing it back in gives a reabsorption pressure of 37 mm Hg - 36 mm Hg = 1 mm Hg. However, we have to add in the interstitial fluid colloid osmotic pressure (0 mm Hg), which pushes fluid back into the capillary, making the final reabsorption pressure 1 mm Hg + 8 mm Hg = 8 mm Hg. Therefore, the answer is C) 8 mm Hg.

Given the Following Parameters,what Would the Reabsorption Pressure Be