The current form of the Milton Bradley board game Life includes a circular spinner that has 10 evenly spaced numbers around the edge, which specify the number of places a character will move.Assuming the spinner is balanced, the outcomes 1 through 10 inclusive are equally likely.On your next turn, you must move more than 4 spaces to be in the lead.However, in your current location on the game board, every other space (each odd space) gives you an undesirable result.What is the probability that on your next turn you will be in the lead and not have an undesirable result?
A) 0.2
B) 0.4
C) 0.3
D) 0.6

Question

Quizplus · Accepted Answer

To be in the lead, we need to move 5 or more spaces. The only way we can have an undesirable result is if we land on an odd space during that move. So, we need to calculate the probability of getting a 5, 6, 7, 8, 9 or 10 on the spinner and not landing on an odd space. 
There are 6 numbers that satisfy this: 5, 6, 7, 8, 9, and 10. The probability of any of them arising is 1/6. However, the probability of not landing on an odd space is 1/2. Therefore, the probability of both events occurring is (1/6) * (1/2) = 1/12. 
Since we need to get a 5 or higher and not land on an odd space, we can add up the probabilities of getting a 5 or higher and subtract the probabilities of landing on an odd space for each of these outcomes:
P(5 or 6) = 1/6 + 1/2 = 2/3
P(7 or 8) = 1/6 + 1/2 = 2/3
P(9 or 10) = 1/6 + 1/2 = 2/3
Therefore, the probability of being in the lead and not having an undesirable result is:
(2/3 + 2/3 + 2/3) / 6 = 6/18 = 1/3 = 0.3.

So the answer is (C) 0.3.

The Current Form of the Milton Bradley Board Game Life