If the percent of the normal curve between the mean and the z-score is .34, then the percentile is .84.

Question

Quizplus · Accepted Answer

This statement is true. If the percent of the normal curve between the mean and the z-score is .34, then the area to the left of the z-score is .5 - .34/2 = .08. Using a standard normal table or calculator, we can find that the z-score corresponding to the .08 percentile is approximately -1.05. Adding the standardized value of the mean (0) to this z-score gives us -1.05, which corresponds to the 15.87th percentile. Taking 1 - 0.1587 = 0.8413, or 84.13%, we can see that the statement's claim is true, within rounding error.

If the Percent of the Normal Curve Between the Mean