Find the limit (if it exists). $$\lim _ { x \rightarrow 11 ^ { + } } \frac { 11 - x } { x ^ { 2 } - 121 }$$
A) $\frac { 1 } { 22 }$
B) 0
C) Limit does not exist.
D) $- \frac { 1 } { 22 }$
E) $\frac { 1 } { 242 }$

Question

Quizplus · Accepted Answer

As $x$ approaches $11$ from the right, $(x-11)$ is negative and $(x^2-121)$ is positive, so we have a negative number over a positive number. Therefore, the limit approaches $-\infty$. The only answer choice given that represents a negative number is $\boxed{	extbf{(D)}\ -\frac{1}{22}}$.

Find the Limit (If It Exists) lim⁡x→11+11−xx2−121\lim _ { x \rightarrow 11 ^ { + } } \frac { 11 - x } { x ^ { 2 } - 121 }x→11+lim​x2−12111−x​

Find the Limit (If It Exists) $\lim _ { x \rightarrow 11 ^ { + } } \frac { 11 - x } { x ^ { 2 } - 121 }$