Set up the definite integral that gives the area of the region bounded by the graph of $y _ { 1 } = x ^ { 2 } + 2 x + 1$ and $y _ { 2 } = 2 x + 5$

A) $\int _ { - 2 } ^ { 2 } \left( - x ^ { 2 } + 4 \right) d x$
B) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 2 x + 1 \right) d x$
C)$\int _ { - 2 } ^ { 2 } \left( - x ^ { 2 } + 4 \right) d y$
D) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 4 x + 6 \right) d y$
E) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 4 x + 6 \right) d x$

Question

Set up the definite integral that gives the area of the region bounded by the graph of $y _ { 1 } = x ^ { 2 } + 2 x + 1$ and $y _ { 2 } = 2 x + 5$

A) $\int _ { - 2 } ^ { 2 } \left( - x ^ { 2 } + 4 \right) d x$ 
B) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 2 x + 1 \right) d x$ 
C)$\int _ { - 2 } ^ { 2 } \left( - x ^ { 2 } + 4 \right) d y$ 
D) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 4 x + 6 \right) d y$ 
E) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 4 x + 6 \right) d x$

Quizplus · Accepted Answer

The Answer of Set up the definite integral that gives the area of the region bounded by the graph of $y _ { 1 } = x ^ { 2 } + 2 x + 1$ and $y _ { 2 } = 2 x + 5$

A) $\int _ { - 2 } ^ { 2 } \left( - x ^ { 2 } + 4 \right) d x$ 
B) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 2 x + 1 \right) d x$ 
C)$\int _ { - 2 } ^ { 2 } \left( - x ^ { 2 } + 4 \right) d y$ 
D) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 4 x + 6 \right) d y$ 
E) $\int _ { - 2 } ^ { 2 } \left( x ^ { 2 } + 4 x + 6 \right) d x$

Set Up the Definite Integral That Gives the Area of the Region