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Question 43
Find the arc length of the graph of the function y=8x32+7 over the interval [0,6]. \text { Find the arc length of the graph of the function } y = 8 x ^ { \frac { 3 } { 2 } } + 7 \text { over the interval } [ 0,6 ] \text {. } Find the arc length of the graph of the function y=8x23+7 over the interval [0,6].
A) 865865−1216\frac { 865 \sqrt { 865 } - 1 } { 216 }216865865−1 B) 865865−864216\frac { 865 \sqrt { 865 } - 864 } { 216 }216865865−864 C) 865865+1432\frac { 865 \sqrt { 865 } + 1 } { 432 }432865865+1 D) 865865+1216\frac { 865 \sqrt { 865 } + 1 } { 216 }216865865+1 E) 865865−1432\frac { 865 \sqrt { 865 } - 1 } { 432 }432865865−1
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Q41: Q42: Q44: Q45: Use the shell method to setQ46: Use the disk or shell methodQ47: Find the arc length of theQ48: Use the disk or the shellUnlock this Answer For Free Now!View this answer and more for free by performing one of the following actionsScan the QR code to install the App and get 2 free unlocksMaximize QR codeUnlock quizzes for free by uploading documentsUpload documents
Q42: Q44: Q45: Use the shell method to setQ46: Use the disk or shell methodQ47: Find the arc length of theQ48: Use the disk or the shell
Q44: Q45: Use the shell method to setQ46: Use the disk or shell methodQ47: Find the arc length of theQ48: Use the disk or the shell
Q45: Use the shell method to set
Q46: Use the disk or shell method
Q47: Find the arc length of the
Q48: Use the disk or the shell
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