Find the arc length of the curve on the given interval. $$x = \sqrt { t } , y = 3 t - 2,0 \leq t \leq 3$$
A) $\frac { \ln ( 864 + 24 \sqrt { 327 } ) + \ln 2 + 12 \sqrt { 327 } } { 24 }$
B) $\frac { \ln ( 864 + 12 \sqrt { 327 } ) - \ln 2 + 6 \sqrt { 327 } } { 24 }$
C) $\frac { \ln ( 864 + 12 \sqrt { 327 } ) + \ln 2 + 12 \sqrt { 165 } } { 48 }$
D) $\frac { \ln ( 864 + 12 \sqrt { 327 } ) + \ln 2 + 12 \sqrt { 165 } } { 24 }$
E) $\frac { \ln ( 864 + 24 \sqrt { 327 } ) - \ln 2 + 12 \sqrt { 327 } } { 24 }$

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The Answer of Find the arc length of the curve on the given interval. $$x = \sqrt { t } , y = 3 t - 2,0 \leq t \leq 3$$
A) $\frac { \ln ( 864 + 24 \sqrt { 327 } ) + \ln 2 + 12 \sqrt { 327 } } { 24 }$
B) $\frac { \ln ( 864 + 12 \sqrt { 327 } ) - \ln 2 + 6 \sqrt { 327 } } { 24 }$
C) $\frac { \ln ( 864 + 12 \sqrt { 327 } ) + \ln 2 + 12 \sqrt { 165 } } { 48 }$
D) $\frac { \ln ( 864 + 12 \sqrt { 327 } ) + \ln 2 + 12 \sqrt { 165 } } { 24 }$
E) $\frac { \ln ( 864 + 24 \sqrt { 327 } ) - \ln 2 + 12 \sqrt { 327 } } { 24 }$

Find the Arc Length of the Curve on the Given x=t,y=3t−2,0≤t≤3x = \sqrt { t } , y = 3 t - 2,0 \leq t \leq 3x=t​,y=3t−2,0≤t≤3

Find the Arc Length of the Curve on the Given $x = \sqrt { t } , y = 3 t - 2,0 \leq t \leq 3$