Factor the expression completely. $3 x ^ { 3 } + 3 x ^ { 2 } - 13 x - 13$
A) $\quad ( x - 1 ) \left( 3 x ^ { 2 } + 13 \right)$
B) $\quad ( 1 - x ) \left( 3 x ^ { 2 } - 13 \right)$
C) $\quad ( x + 1 ) \left( 3 x ^ { 2 } - 13 \right)$
D) $\quad ( x + 1 ) \left( 13 - 3 x ^ { 2 } \right)$

Question

Quizplus · Accepted Answer

We can factor the expression by grouping the terms as follows:
\begin{align*}
3x^3+3x^2-13x-13 &= 3x^2(x+1)-13(x+1) \
&= (x+1)(3x^2-13)\
&= (x+1)(3x^2-3-10) \
&= (x+1)(3x^2-3)-(x+1)(10) \
&= (x+1)(3(x^2-1)-10) \
&= (x+1)(3x-3)(x+1+4) \
&= \boxed{	extbf{(C)}\ (x+1)(3x^2-13)}
\end{align*}

Factor the Expression Completely 3x3+3x2−13x−133 x ^ { 3 } + 3 x ^ { 2 } - 13 x - 133x3+3x2−13x−13

Factor the Expression Completely $3 x ^ { 3 } + 3 x ^ { 2 } - 13 x - 13$