Find the value or values of $c$ that satisfy the equation $\frac { f ( b ) - f ( a ) } { b - a } = f ^ { \prime } ( c )$ in the conclusion of the Mean Value Theorem for the function and interval.
-$f ( x ) = \ln ( x - 1 ) , [ 2,6 ] \quad$ Round to the nearest thousandth.
A) $4.485$
B) $3.485$
C) $3.885$
D) $\pm 3.485$

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The Answer of  Find the value or values of $c$ that satisfy the equation $\frac { f ( b ) - f ( a ) } { b - a } = f ^ { \prime } ( c )$ in the conclusion of the Mean Value Theorem for the function and interval.
-$f ( x ) = \ln ( x - 1 ) , [ 2,6 ] \quad$ Round to the nearest thousandth.
A) $4.485$
B) $3.485$
C) $3.885$
D) $\pm 3.485$

Find the Value or Values Of ccc That Satisfy the Equation f(b)−f(a)b−a=f′(c)\frac { f ( b ) - f ( a ) } { b - a } = f ^ { \prime } ( c )b−af(b)−f(a)​=f′(c)

Find the Value or Values Of $c$ That Satisfy the Equation $\frac { f ( b ) - f ( a ) } { b - a } = f ^ { \prime } ( c )$