Find the limit, if it exists.
-$$\lim _ { x \rightarrow 1 } \frac { 2 x - 7 } { 4 x + 5 }$$
A) $- \frac { 5 } { 9 }$
B) Does not exist
C) $- \frac { 1 } { 2 }$
D) $- \frac { 7 } { 5 }$

Name: Find the limit, if it exists. -\[\lim _ { x \rightarrow 1 } \frac { 2 x - 7 } { 4 x + 5 }\] A) $- \frac { 5 } { 9 }$ B) Does not exist C) $- \frac { 1 } { 2 }$ D) $- \frac { 7 } { 5 }$
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Question

Quizplus · Accepted Answer

To find the limit as $x$ approaches 1, substitute $x = 1$ into the given expression: $\frac{2(1) - 7}{4(1) + 5} = \frac{-5}{9}$.

Find the Limit, If It Exists lim⁡x→12x−74x+5\lim _ { x \rightarrow 1 } \frac { 2 x - 7 } { 4 x + 5 }x→1lim​4x+52x−7​

Find the Limit, If It Exists $\lim _ { x \rightarrow 1 } \frac { 2 x - 7 } { 4 x + 5 }$