The specific gravity of an unknown liquid is known to be 1.26. The liquid is most likely:
A) Glycerin
B) Carbon tetrachloride
C) Mercury
D) Water

Question

Quizplus · Accepted Answer

Glycerin
$$\gamma _ { x } = S \gamma _ { \text {water } } = 1.26 \times 9810 = 12360 \mathrm {~N} / \mathrm { m } ^ { 3 }$$
Reviewing the specific weights of the various liquids in Table B.5 of the Appendix suggests the unknown liquid is glycerin.

The Specific Gravity of an Unknown Liquid Is Known to Be