$\text { Using the probability distribution listed, the mean would be } 1.6 .$
$\begin{array}{ll|l|l|l|}
\hline x & 0 & 1 & 2 & 3 \
\hline P x & 0.2 & 0.1 & 0.3 & 0.4 \
\hline
\end{array}$

Question

Quizplus · Accepted Answer

The expected value or mean of a probability distribution is calculated by multiplying each possible outcome by its probability and summing them up. So, in this case, the mean would be:

$$E(X) = 0(0.2) + 1(0.1) + 2(0.3) + 3(0.4) = 1.7$$

Therefore, the statement that the mean would be 1.6 is false.

Using the probability distribution listed, the mean would be 1.6.\text { Using the probability distribution listed, the mean would be } 1.6 . Using the probability distribution listed, the mean would be 1.6.

$\text { Using the probability distribution listed, the mean would be } 1.6 .$