$$\begin{array}{l}
\text { What probability value would be needed to complete the following probability distribution? }\
\begin{array} { | l | c | c | c | c | c | }
\hline \mathrm { x } & - 2 & - 1 & 0 & 1 & 2 \
\hline \mathrm { P } ( \mathrm { x } ) & 0.16 & 0.17 & & 0.12 & 0.31 \
\hline
\end{array}
\end{array}$$
A) 0.12
B) 0.24
C) 0.41
D) 0.76

Question

$$\begin{array}{l}
\text { What probability value would be needed to complete the following probability distribution? }\
\begin{array} { | l | c | c | c | c | c | } 
\hline \mathrm { x } & - 2 & - 1 & 0 & 1 & 2 \
\hline \mathrm { P } ( \mathrm { x } ) & 0.16 & 0.17 & & 0.12 & 0.31 \
\hline
\end{array}
\end{array}$$
A) 0.12
B) 0.24
C) 0.41
D) 0.76

Quizplus · Accepted Answer

The sum of all probabilities in a probability distribution must equal 1. Adding the given probabilities: 0.16 + 0.17 + 0.12 + 0.31 = 0.76. Therefore, the missing probability is 1 - 0.76 = 0.24.

A) 012 B) 0

A) 012
B) 0