A mortar shell is fired with a muzzle speed of 250 ft/sec.Find the angle of elevation of the mortar if the shell strikes a target located 1100 ft away.Round your answer to 2 decimal places.
A) $17.14 ^ { \circ }$
B) $14.69 ^ { \circ }$
C) $0.3 ^ { \circ }$
D) $0.9 ^ { \circ }$

Question

A mortar shell is fired with a muzzle speed of 250 ft/sec.Find the angle of elevation of the mortar if the shell strikes a target located 1100 ft away.Round your answer to 2 decimal places. 
A) $17.14 ^ { \circ }$
B) $14.69 ^ { \circ }$
C) $0.3 ^ { \circ }$
D) $0.9 ^ { \circ }$

Quizplus · Accepted Answer

The range of a projectile is given by the formula $R = \frac{v^2 \sin 2\theta}{g}$, where $R$ is the range, $v$ is the muzzle speed, $\theta$ is the angle of elevation, and $g$ is the acceleration due to gravity (approximately $32 ft/s^2$ for calculations involving feet). Rearranging the formula to solve for $\theta$ and substituting the given values ($R = 1100 ft$, $v = 250 ft/s$), we can solve for $\theta$. The correct angle of elevation that satisfies this equation is approximately $17.14^\circ$.

A Mortar Shell Is Fired with a Muzzle Speed of 250