Suppose the distance $s$ (in feet) covered by a car moving along a straight road after $t$ sec is given by the function $s = f ( t ) = 3 t ^ { 2 } + 13 t$. Calculate the (instantaneous) velocity of the car when $t = 35$.
A) $223 \mathrm { ft } / \mathrm { sec }$
B) $16 \mathrm { ft } / \mathrm { sec }$
C) $560 \mathrm { ft } / \mathrm { sec }$
D) $4130 \mathrm { ft } / \mathrm { sec }$

Question

Quizplus · Accepted Answer

The instantaneous velocity is the derivative of the distance function with respect to time. So, $v(t) = f'(t) = 6t + 13$. At $t = 35$, the velocity is $v(35) = 6(35) + 13 = 223$ ft/sec.

Suppose the Distance sss (In Feet) Covered by a Car Moving Along a Straight

Suppose the Distance $s$ (In Feet) Covered by a Car Moving Along a Straight