At 4:00 P.M. a car's speedometer reads $29 \mathrm { mi } ^ { 2 }$. At 4:15 it reads $72 \mathrm { mi } / \mathrm { h } ^ { 2 }$. At some time between $4 : 00$ and $4 : 15$ the acceleration is exactly $x \mathrm { mi } ^ { 2 } \mathrm {~h} ^ { 2 }$. Find $x$.

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The Answer of At 4:00 P.M. a car's speedometer reads $29 \mathrm { mi } ^ { 2 }$. At 4:15 it reads $72 \mathrm { mi } / \mathrm { h } ^ { 2 }$. At some time between $4 : 00$ and $4 : 15$ the acceleration is exactly $x \mathrm { mi } ^ { 2 } \mathrm {~h} ^ { 2 }$. Find $x$.

At 4:00 PM 29mi229 \mathrm { mi } ^ { 2 }29mi2

At 4:00 PM $29 \mathrm { mi } ^ { 2 }$