Find the limit.
$\lim _ { t \rightarrow \infty } \left( \frac { 8 t ^ { 2 } + 7 } { 9 t ^ { 2 } - 7 } \right) e ^ { - 03 t }$
A) 0
B) $\frac { 9 } { 8 }$
C) $\frac { 8 } { 9 }$
D) $- \frac { 7 } { 8 }$

Question

Quizplus · Accepted Answer

As $ t \rightarrow \infty $, the exponential term $ e ^ { - 03 t } \rightarrow 0 $, so the limit is 0.

Find the Limit lim⁡t→∞(8t2+79t2−7)e−03t\lim _ { t \rightarrow \infty } \left( \frac { 8 t ^ { 2 } + 7 } { 9 t ^ { 2 } - 7 } \right) e ^ { - 03 t }limt→∞​(9t2−78t2+7​)e−03t

Find the Limit $\lim _ { t \rightarrow \infty } \left( \frac { 8 t ^ { 2 } + 7 } { 9 t ^ { 2 } - 7 } \right) e ^ { - 03 t }$