Evaluate the integral using the indicated trigonometric substitution.
$$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 25 } } d x ; \quad x = 5 \tan \theta$$

Name: Evaluate the integral using the indicated trigonometric substitution. \[\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 25 } } d x ; \quad x = 5 \tan \theta\]
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The Answer of Evaluate the integral using the indicated trigonometric substitution.
$$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 25 } } d x ; \quad x = 5 \tan \theta$$

Evaluate the Integral Using the Indicated Trigonometric Substitution ∫x3x2+25dx;x=5tan⁡θ\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 25 } } d x ; \quad x = 5 \tan \theta∫x2+25​x3​dx;x=5tanθ

Evaluate the Integral Using the Indicated Trigonometric Substitution $\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 25 } } d x ; \quad x = 5 \tan \theta$