Solve the differential equation using the method of variation of parameters.
$$y ^ { tt } + y = \sec x , \frac { \pi } { 4 }

Name: Solve the differential equation using the method of variation of parameters. \[y ^ { tt } + y = \sec x , \frac { \pi } { 4 } < x < \frac { \pi } { 2 }\]
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Question

Solve the differential equation using the method of variation of parameters.
$$y ^ { tt } + y = \sec x , \frac { \pi } { 4 } < x < \frac { \pi } { 2 }$$

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The Answer of Solve the differential equation using the method of variation of parameters.
$$y ^ { tt } + y = \sec x , \frac { \pi } { 4 } < x < \frac { \pi } { 2 }$$

Solve the Differential Equation Using the Method of Variation of Parameters