Factor completely.
-$$98 x ^ { 2 } - 128$$
A) $2 ( 7 x + 8 ) ( 7 x - 8 )$
B) $( 14 x + 16 ) ( 7 x - 8 )$
C) $2 ( 7 x - 8 ) ^ { 2 }$
D) $( 7 x + 8 ) ( 14 x - 16 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is 2, to get $2(49x^2 - 64)$. Then, recognize that $49x^2$ and $64$ are perfect squares, so the expression can be factored as a difference of squares: $2(7x)^2 - 2(8)^2$, which simplifies to $2(7x + 8)(7x - 8)$.

Factor Completely 98x2−12898 x ^ { 2 } - 12898x2−128 A) 2(7x+8)(7x−8)2 ( 7 x + 8 ) ( 7 x - 8 )2(7x+8)(7x−8)

Factor Completely $98 x ^ { 2 } - 128$ A) $2 ( 7 x + 8 ) ( 7 x - 8 )$