Use a double-angle formula or half-angle formula to simplify $\frac { \sin 48 ^ { \circ } } { 1 + \cos 48 ^ { \circ } }$
A) $\tan 48 ^ { \circ }$
B) $\tan 24 ^ { \circ }$
C) $\csc 24 ^ { \circ }$
D) $\cot 48 ^ { \circ }$
E) $1 + \sin 24 ^ { \circ }$

Question

Quizplus · Accepted Answer

The expression can be simplified using the half-angle formula for sine, which is $\sin \theta = \frac{2 \sin(\theta/2) \cos(\theta/2)}{2 \cos^2(\theta/2)}$. Applying this to the given expression, we get $\frac{\sin 48^\circ}{1 + \cos 48^\circ} = \frac{2 \sin(24^\circ) \cos(24^\circ)}{2 \cos^2(24^\circ)} = \tan 24^\circ$.

Use a Double-Angle Formula or Half-Angle Formula to Simplify sin⁡48∘1+cos⁡48∘\frac { \sin 48 ^ { \circ } } { 1 + \cos 48 ^ { \circ } }1+cos48∘sin48∘​

Use a Double-Angle Formula or Half-Angle Formula to Simplify $\frac { \sin 48 ^ { \circ } } { 1 + \cos 48 ^ { \circ } }$