Find the reference number and the terminal point $p ( x , y )$ determined by $t = - \frac { 11 \pi } { 6 }$
A) $- \frac { \pi } { 6 }$, $P ( x , y ) = \left( \frac { - \sqrt { 5 } } { 2 } , - \frac { 1 } { 2 } \right)$

B) $\pi$, $P ( x , y ) = ( - 1,0 )$

C) $\frac { \pi } { 6 }$, $D ( x , y ) = \left( \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)$

D) $\frac { \pi } { 3 }$, $p ( x , y ) = \left( \frac { 1 } { 2 } , \frac { \sqrt { 5 } } { 2 } \right)$

E) $\frac { 11 \pi } { 6 }$, $p ( x , y ) = \left( - \frac { - \sqrt {5 } } { 2 } , - \frac { 1 } { 2 } \right)$

Question

Find the reference number and the terminal point $p ( x , y )$ determined by $t = - \frac { 11 \pi } { 6 }$
A) $- \frac { \pi } { 6 }$, $P ( x , y ) = \left( \frac { - \sqrt { 5 } } { 2 } , - \frac { 1 } { 2 } \right)$

B) $\pi$, $P ( x , y ) = ( - 1,0 )$

C) $\frac { \pi } { 6 }$, $D ( x , y ) = \left( \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)$

D) $\frac { \pi } { 3 }$, $p ( x , y ) = \left( \frac { 1 } { 2 } , \frac { \sqrt { 5 } } { 2 } \right)$

E) $\frac { 11 \pi } { 6 }$, $p ( x , y ) = \left( - \frac { - \sqrt {5 } } { 2 } , - \frac { 1 } { 2 } \right)$

Quizplus · Accepted Answer

The reference angle for $t = -\frac{11\pi}{6}$ is $\frac{\pi}{6}$, and the terminal point on the unit circle for this angle is $\left(\frac{\sqrt{3}}{2}, \frac{1}{2}\right)$.

Find the Reference Number and the Terminal Point p(x,y)p ( x , y )p(x,y)

Find the Reference Number and the Terminal Point $p ( x , y )$