If the Terminal Point Determined by T Is $\left( \frac { 12 } { 13 } , - \frac { 5 } { 13 } \right)$

If the terminal point determined by t is $\left( \frac { 12 } { 13 } , - \frac { 5 } { 13 } \right)$ , find $\sin t$ , $\cos t$ And $\tan t$

A) $\sin ( t ) = \frac { 12 } { 13 }$ , $\cos \left( t ^ { \prime } \right) = \frac { 5 } { 13 }$ , $\tan ( t ) = \frac { 5 } { 12 }$

B) $\sin ( t ) = - \frac { 5 } { 13 }$ , $\cos (t) =\frac{12}{13}$ , $\tan ( t ) = - \frac { 5 } { 12 }$

C) $\sin ( t ) = \frac { 5 } { 13 }$ , $\cos ( t ) = - \frac { 12 } { 13 }$ , $\tan ( t ) = - \frac { 13 } { 12 }$

D) $\sin ( t ) = - \frac { 5 } { 13 }$ , $\cos = \frac { 12 } { 13 }$ , $\tan ( t ) = - \frac { 12 } { 5 }$

E) $\sin ( t ) = - \frac { 5 } { 13 }$ , $\cos = \frac { 12 } { 13 }$ , $\text { tant } t = \frac { 12 } { 5 }$