Find the values of $\sec \theta$ and $\cot \theta$If the point $( - 3,4 )$Is on the terminal side of $\theta$

A) $\sec \theta = - \frac { 4 } { 3 }$
, $\cot \theta = - \frac { 3 } { 4 }$

B) $\sec \theta = - \frac { 5 } { 3 }$
, $\cot \theta = - \frac { 3 } { 4 }$

C) $\sec \theta = - \frac { \sqrt { 7 } } { 3 }$
, $\cot \theta = \frac { 5 } { 4 }$

D) $\sec \theta = - \frac { \sqrt { 7 } } { 3 }$
, $\cot \theta = - \frac { 3 } { 4 }$

E) $\sec \theta = - \frac { 5 } { 3 }$
, $\cot \theta = \frac { 4 } { 3 }$

Question

Find the values of $\sec \theta$ and $\cot \theta$If the point $( - 3,4 )$Is on the terminal side of $\theta$

A) $\sec \theta = - \frac { 4 } { 3 }$
, $\cot \theta = - \frac { 3 } { 4 }$

B) $\sec \theta = - \frac { 5 } { 3 }$
, $\cot \theta = - \frac { 3 } { 4 }$

C) $\sec \theta = - \frac { \sqrt { 7 } } { 3 }$
, $\cot \theta = \frac { 5 } { 4 }$

D) $\sec \theta = - \frac { \sqrt { 7 } } { 3 }$
, $\cot \theta = - \frac { 3 } { 4 }$

E) $\sec \theta = - \frac { 5 } { 3 }$
, $\cot \theta = \frac { 4 } { 3 }$

Quizplus · Accepted Answer

Given a point $(-3, 4)$ on the terminal side of $\theta$, we can find the values of $\sec \theta$ and $\cot \theta$ using trigonometric definitions. The radius $r = \sqrt{(-3)^2 + 4^2} = 5$. Thus, $\sec \theta = \frac{1}{\cos \theta} = \frac{r}{x} = \frac{5}{-3} = -\frac{5}{3}$ and $\cot \theta = \frac{1}{\tan \theta} = \frac{x}{y} = \frac{-3}{4}$.

Find the Values Of sec⁡θ\sec \thetasecθ And cot⁡θ\cot \thetacotθ If the Point (−3,4)( - 3,4 )(−3,4)

Find the Values Of $\sec \theta$ And $\cot \theta$ If the Point $( - 3,4 )$