Evaluate $f ( - 1 )$ , $f ( 0 )$, $f ( 1 )$
, for the piecewise-defined function. $$f ( x ) = \left\{ \begin{array} { l l }
x ^ { 2 } & \text { if } x

Question

Evaluate $f ( - 1 )$ , $f ( 0 )$, $f ( 1 )$
, for the piecewise-defined function. $$f ( x ) = \left\{ \begin{array} { l l } 
x ^ { 2 } & \text { if } x < 0 \
2 x - 1 & \text { if } x \geq 0
\end{array} \right.$$
A) $f ( - 1 ) = 1 , f ( 0 ) = - 1 , f ( 1 ) = 1$
B) $f ( - 1 ) = - 3 , f ( 0 ) = 0 , f ( 1 ) = 1$
C) $f ( - 1 ) = - 1 , f ( 0 ) = 0 , f ( 1 ) = 1$
D) $f ( - 1 ) = 3 , f ( 0 ) = 1 , f ( 1 ) = - 3$
E) none of these

Quizplus · Accepted Answer

For $f(-1)$, since $-1 < 0$, we use $x^2$, so $f(-1) = (-1)^2 = 1$. For $f(0)$, since $0 \geq 0$, we use $2x - 1$, so $f(0) = 2(0) - 1 = -1$. For $f(1)$, since $1 \geq 0$, we use $2x - 1$, so $f(1) = 2(1) - 1 = 1$.

Evaluate f(−1)f ( - 1 )f(−1) f(0)f ( 0 )f(0) f(1)f ( 1 )f(1)

Evaluate $f ( - 1 )$ $f ( 0 )$ $f ( 1 )$