Find the vertices of the hyperbola. $\frac { x ^ { 2 } } { 64 } - \frac { y ^ { 2 } } { 36 } = 1$
A) $V ( \pm 8 , \pm 6 )$
B) $V ( \pm 6,0 )$
C) $V ( \pm 8,0 )$
D) $V ( 0 , \pm 8 )$
E) none of these

Question

Quizplus · Accepted Answer

The vertices of a hyperbola of the form $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$ are located at $(\pm a, 0)$. For the given hyperbola $\frac{x^2}{64} - \frac{y^2}{36} = 1$, $a^2 = 64$, so $a = \pm 8$. Therefore, the vertices are $(\pm 8, 0)$.

Find the Vertices of the Hyperbola x264−y236=1\frac { x ^ { 2 } } { 64 } - \frac { y ^ { 2 } } { 36 } = 164x2​−36y2​=1

Find the Vertices of the Hyperbola $\frac { x ^ { 2 } } { 64 } - \frac { y ^ { 2 } } { 36 } = 1$