Consider the following code snippet: public static void fun(T[] t) { ...} Erasure by the compiler of method fun will generate which result? A)public static void fun(Object[] t) { ...} B)public static void fun(Object[] t) { ...} C)public static void fun(Object t) { ...} D)public static

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Quizplus · Accepted Answer

The erasure of a generic method replaces all type parameters with their bounds, which in this case is Object. Therefore, the erasure of the method fun will generate public static void fun(Object[] t) { ...}.

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