Solve the following equation for $x$ accurate to three decimal places. $2 \left( 2 ^ { 2 x - 3 } \right) = 290$
A) $x = - 34.750$
B) $x = 37.750$
C) $x = - 2.090$
D) $x = 5.090$
E) $x = - 32.707$

Question

Quizplus · Accepted Answer

First, divide both sides by 2 to get $2^{2x-3} = 145$. Then, apply the logarithm to both sides to solve for $x$, leading to $x = 5.090$.

Solve the Following Equation For xxx Accurate to Three Decimal Places 2(22x−3)=2902 \left( 2 ^ { 2 x - 3 } \right) = 2902(22x−3)=290

Solve the Following Equation For $x$ Accurate to Three Decimal Places $2 \left( 2 ^ { 2 x - 3 } \right) = 290$